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=4.phi.r1^2:4.phi.r2^2:4.phi.r3^2
=r1^2 : r2^2 : r3^2
=4^2 : 6^2 : 10^2
=16 : 36 : 100
=4 : 9 : 25
= 4πr²
dikarenakan 4 dan π senilai, maka :
bola 1 : bola 2 : bola 3
= (r1)² : (r2)² : (r3)²
= (4)² : (6)² : (10)²
= 16 : 36 : 100
bagi dengan 4
= 4 : 9 : 10 --------------------> perbandingan luas sisi ketiga bola.