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- Rangkaian Arus Searah
n = 3
E = 1,5 V
r = 0,2 Ω
R seperti pada foto
i = __ ?
Vj = __ ?
Hambatan luar
R = 1,9 + (1/2 + 1/6)⁻¹
= 1,9 + (⁴/₆)⁻¹
= 1,9 + 1,5
= 3,4 Ω
Kuat arus induk
i = nE / (R + nr)
= 3·1,5 / (3,4 + 3·0,2)
= 4,5 / (3,4 + 0,6)
= 4,5 / 4
= 1¹/₈ = 1,125 A ← jwb
Kuat arus cabang
i₁ : i₂ = 1/2 : 1/6 = 3 : 1
i₁ = ³/₄ · 1,125 A = ²⁷/₃₂ = 0,84375 A ← jwb
i₂ = ¹/₄ · 1,125 A = ⁹/₃₂ = 0,28125 A ← jwb
Tegangan jepit
Vj = i R
= 1,125 · 3,4
= 3,825 V ← jwb