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Barisan Geometri : a + 10 , a + 16 , a + 25
Rasio = a + 16 = a + 25
a + 10 a + 16
(a+16)² = (a+10)(a+25)
⇔ a² + 32a + 256 = a² + 35a + 250
⇔ a² - a² + 35a - 32a = 256 - 250
3a = 6 ⇔ a = 6/3 ⇔ a = 2
Rasio atau r = 2+16 = 18/12 = 3/2
2 + 10
Barisan Aritmetika : 2 , 18 , 34 maka jumlah barisan aritmetika S3 = 2 + 18 + 34 = 54
Barisan Geometri : 12 , 18 , 27 maka jumlah barisan geometri S3 = 12 + 18 + 27 = 57