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L= 2sincos/1-1+2sin²=2sincos/2sin²=cos/sin=ctga
1-cos2a różne od 0
b)L=tg/2tg/1-tg²-tga*=tg/2tg-tg+tg³/1-tg²=tg*1-tg²/tg-tg³=tg(1-tg²)/tg(1+tg²)=cos2a
dla tg2a-tga różnego od zera i tga różnego od π/2+kπ
*(troche nieczytelne http://sciaga.onet.pl/12581,59,,,1,19580,sciaga.html z tej strony wzór na tg2a)