(tg 150-cos60):sin135= ??
tg 150=tg(180-30)= -tg30=-
cos60=1/2
sin135=sin(180-45) sin45=
(-*1/2)/= -
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tg 150=tg(180-30)= -tg30=-
cos60=1/2
sin135=sin(180-45) sin45=
(-*1/2)/= -