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du = 2x+ 2 dx
du = 2(x+1) dx
(x+1) dx = 1/2 du.
.
batas inetrgal
u = x² + 2x + 2
x = 1 --> u = 5
x = 0--> u = 2
₀¹∫ (x+1)/(x²+2x+2)² dx = ₂⁵∫(¹/₂ u⁻²) du
= - ¹/₂ [ 1/u]⁵₂
= - ¹/₂ { 1/5 - 1/2 }
= - ¹/₂ {⁻³/₁₀}
= ³/₂₀