Jawaban:
765
Penjelasan dengan langkah-langkah:
Jika 1 + 2 + 3... + 100 = 5050
Barisan dan deret Aritmatika
U1 = 1 = a
U2 = 2 = a + (n-1)b
b = 1
U100 = 100
S100 = 100/2(a + U100)
= 50(1 + 100)
= 50(101)
= 5050 ✓
Dengan rumus dan metode yg sama, kita mencoba terapkan pada materi quiz;
maka 11 + 12 + ...+ 40 =
U1 = 11 = a
U2 = 12 = a + (n-1)b
maka
40 = a +(n-1)b
40 = 11 + (n - 1)1
40 = 11 + n - 1
n = 30
U30 = 40
S30 = 30/2(a + U30)
= 15(11 + 40)
= 15(51)
= 765 ✓
SOAL :
maka 11 + 22 + ... + 40 = ...
JAWAB :
40 = 11 + (n - 1(1)
40 = 11 + (1(n) - (1(1)
40 = 11 + 1n - 1
n = 40 - (11 - 1)
n = 40 - 10
MAKA :
S30 = (30 ÷ 2 × (11 + 40)
= (15/1 × 51)
= (15 × 51)
= 765
KESIMPULAN :
S30 = 765
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Verified answer
Jawaban:
765
Penjelasan dengan langkah-langkah:
Jika 1 + 2 + 3... + 100 = 5050
Barisan dan deret Aritmatika
U1 = 1 = a
U2 = 2 = a + (n-1)b
b = 1
U100 = 100
S100 = 100/2(a + U100)
= 50(1 + 100)
= 50(101)
= 5050 ✓
Dengan rumus dan metode yg sama, kita mencoba terapkan pada materi quiz;
maka 11 + 12 + ...+ 40 =
U1 = 11 = a
U2 = 12 = a + (n-1)b
b = 1
maka
40 = a +(n-1)b
40 = 11 + (n - 1)1
40 = 11 + n - 1
n = 30
U30 = 40
S30 = 30/2(a + U30)
= 15(11 + 40)
= 15(51)
= 765 ✓
SOAL :
Jika 1 + 2 + 3... + 100 = 5050
maka 11 + 22 + ... + 40 = ...
JAWAB :
40 = 11 + (n - 1(1)
40 = 11 + (1(n) - (1(1)
40 = 11 + 1n - 1
40 = 11 + n - 1
n = 40 - (11 - 1)
n = 40 - 10
n = 30
MAKA :
S30 = (30 ÷ 2 × (11 + 40)
= (15/1 × 51)
= (15 × 51)
= 765
KESIMPULAN :
U30 = 40
S30 = 765