Question

Q.
[tex] \\ \\ f(y) = {y}^{2} + 21 \times {15}^{2} \\ f( 2) =... \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ [/tex]

Pake cara !¡

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Answer 1

Diketahui :

f(y) = y² + 21 × 15²

Ditanya :

f(2) = ?

Jawab :

f(y) = y² + 21 × 15²

f(2) = 2² + 21 × 15²

f(2) = ( 2 × 2 ) + 21 × 15²

f(2) = 4 + 21 × 15²

f(2) = 4 + 21 × ( 15 × 15 )

f(2) = 4 + 21 × 225

f(2) = 4 + ( 21 × 225 )

f(4) = 4 + 4.725

f(4) = 4.729

• Jadi, hasil dari f(2) adalah 4.729

Answer 2

f(y) = y² + 21 × 15²

f(2) = 2² + 21 × ( 15 × 15 )

f(2) = ( 2 × 2 ) + 21 × 225

f(2) = 4 + ( 21 × 225 )

f(2) = 4 + 4.725

f(2) = 4.729