Question

Q.MATH

menyederhanakan bentuk akar dan bentuk bilangan pangkat

√100 + √50 =
√24 + √68 =

[tex](5^{2})^{3} + {5}^{2} = [/tex]
[tex] \frac{7^{5} }{7^{6} } = [/tex]
#No ngasal
#No Copas ( Boleh kalkulator kalau susah )
# Semoga Berhasil #

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Answer 1

Jawab:
√100 + √50 = 10+5√2
√24 + √68 = 2(√6+√17)
(5²)³ + 5² = 5⁶ + 5²
7⁵ ÷ 7⁶ = ¹/₇

Penjelasan dengan langkah-langkah:
√100 + √50 =
10 + √(25·2) =
10+√25√2 =
10+5√2
-------------------------
√24 + √68 =
√(4·6)+√(4·17) =
√4(√6+√17) =
2(√6+√17)
-------------------------
(5²)³ + 5² = 5²((5²)²+1)
= 5²(5⁴+1) = 5²(5⁴) + 5² =
5⁶ + 5²
-------------------------
7⁵ ÷ 7⁶ = 7⁵⁻⁶ = 7⁻⁽⁶⁻⁵⁾
= 7⁻¹ = ¹/₇

(xcvi)