∫ 2x + 5 dx =∫ 2x dx + ∫ 5 dx =--------------------------∫ axⁿ dx = ᵃ/ₙ₊₁ xⁿ⁺¹, ∫ n dx = nxoleh karena itu²/₁₊₁ x¹⁺¹ + 5x + C =²/₂ x² + 5x + C =x² + 5x + C
Nilai dari ∫ (2x + 5) dx =
x² + 5x + C
Pembahasan :
∫ (axⁿ ) dx =
a/(n+1) .xⁿ⁺¹ + C
∫ (2x + 5) dx =
2/(1+1) .x¹⁺¹ + 5/(0+1) .x⁰⁺¹ + C =
2/2 .x² + 5/1 .x + C =
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∫ 2x + 5 dx =
∫ 2x dx + ∫ 5 dx =
--------------------------
∫ axⁿ dx = ᵃ/ₙ₊₁ xⁿ⁺¹,
∫ n dx = nx
oleh karena itu
²/₁₊₁ x¹⁺¹ + 5x + C =
²/₂ x² + 5x + C =
x² + 5x + C
Nilai dari ∫ (2x + 5) dx =
x² + 5x + C
Pembahasan :
∫ (axⁿ ) dx =
a/(n+1) .xⁿ⁺¹ + C
∫ (2x + 5) dx =
2/(1+1) .x¹⁺¹ + 5/(0+1) .x⁰⁺¹ + C =
2/2 .x² + 5/1 .x + C =
x² + 5x + C