Question

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[tex]2 \sqrt[3]{4} ( \sqrt[3]{2} + \sqrt[3]{16} ) = \dots[/tex]
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Hitungnya pake sifat eksponen ya, jangan desimal <3
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Selamat Berjuang ​

Answer 1

Jawab:

Penjelasan dengan langkah-langkah:

V = akar

^ = pangkat

2 (³V4) ((³V2) + (³V16)) =

2 (4^⅓) ((2^⅓) + (16^⅓)) =

2 ((2²)^⅓) ((2^⅓) + ((2⁴)^⅓)) =

2 (2^⅔) ((2^⅓) + (2^(4/3))) =

2 (2^⅔) (2^⅓) + 2 (2^⅔) (2^(4/3)) =

2^(1 + ⅔ + ⅓) + 2^(1 + ⅔ + (4/3)) =

2² + 2³ =

4 + 8 = 12

Answer 2

PEMBAHASAN

Eksponen

ⁿ√a × ⁿ√b = ⁿ√(ab)

ⁿ√aⁿ = a

◆

2 ³√4 (³√2 + ³√16)

= 2 (³√(4 × 2) + ³√(4 × 16))

= 2 (³√(2³) + ³√(4³))

= 2 (2 + 4)

= 12