f(y) = y ÷ y + y - y × y + y
f(1) = 1 ÷ 1 + 1 - 1 × 1 + 1
f(1) = 1 + 1 - 1 × 1 + 1
f(1) = 1 + 1 - 1 + 1
f(1) = 1 + 1 - 0
f(1) = 1 + 1
f(1) = 2
Diketahui :
f(x) = y ÷ y + y - y × y + y
Ditanya :
f(1) = ?
Jawab :
f(1) = ( 1 ÷ 1 ) + 1 - 1 × 1 + 1
f(1) = 1 + 1 - ( 1 × 1 ) + 1
f(1) = ( 1 + 1 ) - 1 + 1
f(1) = 2 - 1 + 1
f(1) = ( 2 - 1 ) + 1
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f(y) = y ÷ y + y - y × y + y
f(1) = 1 ÷ 1 + 1 - 1 × 1 + 1
f(1) = 1 + 1 - 1 × 1 + 1
f(1) = 1 + 1 - 1 + 1
f(1) = 1 + 1 - 0
f(1) = 1 + 1
f(1) = 2
:)
Diketahui :
f(x) = y ÷ y + y - y × y + y
Ditanya :
f(1) = ?
Jawab :
f(x) = y ÷ y + y - y × y + y
f(1) = 1 ÷ 1 + 1 - 1 × 1 + 1
f(1) = ( 1 ÷ 1 ) + 1 - 1 × 1 + 1
f(1) = 1 + 1 - 1 × 1 + 1
f(1) = 1 + 1 - ( 1 × 1 ) + 1
f(1) = 1 + 1 - 1 + 1
f(1) = ( 1 + 1 ) - 1 + 1
f(1) = 2 - 1 + 1
f(1) = ( 2 - 1 ) + 1
f(1) = 1 + 1
f(1) = 2