Question

Q. Spesial liburan


Diketahui f(x) = 3x⁴ - 5x³ - x² + 10x - 11 Maka tentukan
[tex]1. \: \rm{f'(x) = ?}[/tex]
[tex]2. \: \rm{f(-1) = ?}[/tex]​

Answer 1

Jawaban:

198

Penjelasan dengan langkah-langkah:

f(11) = 3(-1)⁴ - 5(-1)³ - (-1)² + 10(-1) - 11

f(11) = (-3)⁴ - (-5)³ - (-1) + (-10) - 11

f(11) = ((-3)x(-3)x(-3)x(-3)) - ((-5)x(-5)x(-5))-(-1)+(-10)-11

f(11) = 71 - (-125) - (-1) + (-10) + 11

f(11) = 196 - (-1) +(-10) + 11

f(11) = 197 + (-10) + 11

f(11) = 187 + 11

f(11) = 198

Answer 2

Diketahui :

f(x) = 3x⁴ - 5x³ - x² + 10x - 11

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Ditanya :

1. turunan pertama?

2. Nilai f(-1)?

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Langkah – Langkah :

→ turunan pertama

f(x) = 3x⁴ - 5x³ - x² + 10x - 11

f'(x) = 4.3x⁴-¹ – 3.5x³-¹ – x²-¹ + 10x°-¹

f'(x) = 12x³– 15x² – x¹ + 10

f'(x) = 12x³ – 15x² – x + 10

→ nilai f(-1)

f(x) = 3x⁴ - 5x³ - x² + 10x - 11

f(-1) = 3(-1)⁴ - 5(-1)³ - (-1)² + 10(-1) - 11

f(-1) = 3(1) - 5(-1) - 1 + 10(-1) - 11

f(-1) = 3 - (-5) - 1 + (-10) - 11

f(-1) = 8 - 1 + (-10) - 11

f(-1) = 7 + (-10) - 11

f(-1) = (-3) - 11

f(-1) = (-14)