Odpowiedź:
f '[tex]_x ( x, y) = 2 x*y^5 + 3y*cos x + 2*e^y[/tex]
[tex]f '_y ( x, y ) = x^{2} *5y^4 + 3 sin x + 2x*e^y[/tex]
więc
[tex]f ''_{xx} ( x, y) = 2 y^5 - 3 y*sin x[/tex]
[tex]f ''_{xy} ( x, y) = 10 x*y^4 + 3 cos x + 2 e^y[/tex]
[tex]f ''_{yx} ( x, y) = 10 x* y^4 + 3 cos x +2 e^y[/tex]
[tex]f ''_{yy} ( x, y ) = 20 x^2*y^3 +2 x*e^y[/tex]
Szczegółowe wyjaśnienie:
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Odpowiedź:
f '[tex]_x ( x, y) = 2 x*y^5 + 3y*cos x + 2*e^y[/tex]
[tex]f '_y ( x, y ) = x^{2} *5y^4 + 3 sin x + 2x*e^y[/tex]
więc
[tex]f ''_{xx} ( x, y) = 2 y^5 - 3 y*sin x[/tex]
[tex]f ''_{xy} ( x, y) = 10 x*y^4 + 3 cos x + 2 e^y[/tex]
[tex]f ''_{yx} ( x, y) = 10 x* y^4 + 3 cos x +2 e^y[/tex]
[tex]f ''_{yy} ( x, y ) = 20 x^2*y^3 +2 x*e^y[/tex]
Szczegółowe wyjaśnienie: