[tex]Q. (2/3)[/tex] 1.[tex]\lim_{x \to 2} \frac{x^{2} - 3x + 2}{x - 1}[/tex] 2. [tex]\lim

Eutopya

Nomor 1

Cara 1

$\displaystyle \tt\lim_{x \to 2} \frac{x^{2} - 3x + 2}{x - 1}$

$\displaystyle \tt \: \: \: \: \: = \frac{ \cancel{(x - 1)}( x- 2)}{ \cancel{x - 1}}$

$\displaystyle \tt \: \: \: \: \: = x - 2$

$\displaystyle \tt \: \: \: \: \: = 2 - 2$

$\displaystyle \tt \: \: \: \: \: = 0$

$\\$

Cara 2

$\displaystyle \sf\lim_{x \to 2} \frac{x^{2} - 3x + 2}{x - 1}$

$\displaystyle \sf \: \: \: \: \: = \frac{ {2}^{2} - 3(2) + 2 }{2 - 1}$

$\displaystyle \sf \: \: \: \: \: = \frac{4- 6+ 2 }{1}$

$\displaystyle \sf \: \: \: \: \: = \frac{0}{1}$

$\displaystyle \sf \: \: \: \: \: = 0$

$></p><h2>Nomor 2</h2><p><img src=$

$\displaystyle \tt\lim_{n \to 0} \frac{ \bcancel{x}( {6x}^{4} - 4)}{ \bcancel{x}( {2x}^{3} + 1)}$

$\displaystyle \tt \: \: \: \: \: = \frac{ {6x}^{4} - 4}{ {2x}^{3} + 1}$

$\displaystyle \tt \: \: \: \: \: = \frac{ {6(0)}^{4} - 4}{ {2(0)}^{3} + 1}$

$\displaystyle \tt \: \: \: \: \: = \frac{0 - 4}{0 + 1}$

$\displaystyle \tt \: \: \: \: \: = \frac{- 4}{ 1}$

$\displaystyle \tt \: \: \: \: \: = - 4$

$\\$

#LearnWithPanda

Eutopya Oke

ainyazzura yoshi

ainyazzura btw tumben gada lampiran kyk "answer by panda"?_.

Eutopya Brainly versi 5.2.12 gak bisa naruh lampiran :'

ainyazzura ohh versi lama?_.

Eutopya iya

ainyazzura hoo

Eutopya Ngikut ayah

Eutopya Eh maksudnya ngikut papa

bayujr01

Jawaban :

Lim x^2 - 3x + 2

x-->2 ------------------ = 1

x - 1

Lim 6x^5 - 4x

n-->0 --------------- = - 4

2x^4 + x

Penjelasan :

Lim x^2 - 3x + 2

x-->2 ------------------

x - 1

Lim 2x - 3 + 0

x-->2 ---------------

1 - 0

2(2) - 3

=> ------------

=> 4 - 3

=> 1

Jadi limit x^2 - 3x +2

x-->2 ---------------- adalah 1

x - 1

Lim 6x^5 - 4x

n-->0 --------------

2x^4 + x

Lim 30x^4 - 4

n-->0 --------------

8x^3 + 1

Lim 30n^4 - 4

n-->0 --------------

8n^3 + 1

30(0^4) - 4

=> ----------------

8(0^3) + 1

- 4

=> ------

=> - 4

Jadi limit 6x^5 - 4x

n-->0 -------------- adalah - 4

2x^4 + x

ratsuAisu hasilnya yg soal pertama 1 atau 0 kak?;-;

bayujr01 maaf sbelumnya klo mnurut bayu,penyelesaian limit terlebih dahulu dicari invers nya,setelah itu baru dimasukkan x mendekati angka berapa,begitu nh klo masih ragu coba buka apk lainnya yach,mkasi

ainyazzura ohh

Nomor 1

Recommend Questions

Life Enjoy

Get in touch

Social