Penjelasan dengan langkah-langkah:
7 × 6 × 5 × 4 × 3 × 2 =
42 × 5 × 4 × 3 × 2 =
210 × 4 × 3 × 2 =
840 × 3 × 2 =
2.520 × 2 =
5.040
__________________
7! + 3! =
( 7 x 6 x 5 x 4 x 3 x 2 x 1 ) + ( 3 x 2 x 1 ) =
5.040 + 6 =
5.046
[tex] \tt \frac{1}{2} + \frac{1}{4} = \\ [/tex]
[tex] \tt \frac{2}{4} + \frac{1}{4} = \purple{ \boxed{ \tt \frac{3}{4} }} \\ [/tex]
_______________________________
________________________________
Mapel : matematika
Kelas : 12
Bab : Bab 7 - kaidah pepecahan
Kode soal : 2
Kode Kategorisasi : 12.2.7
Kata Kunci : permutasi, kombinasi, faktorial
_____________________
@rasyidafd.ca
#TingkatkanPrestasimu
1. 7 × 6 × 5 × 4 × 3 × 2
= 42 × 5 × 4 × 3 × 2
= 210 × 4 × 3 × 2
= 840 × 3 × 2
= 2.520 × 2
= 5.040
2. 7! + 3!
= ( 7 × 6 × 5 × 4 × 3 × 2 ) + ( 3 × 2 × 1 )
= ( 42 × 5 × 4 × 3 × 2 ) + ( 6 × 1 )
= ( 210 × 4 × 3 × 2) + 6
= ( 840 × 3 × 2 ) + 6
= ( 2.520 × 2 ) + 6
= 5.040 + 6
= 5.046
3. ½ + ¼ =
../4 + ¼
= (4 ÷ 2 × 1)/4 + ¼
= 2/4 + ¼
= ¾
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Penjelasan dengan langkah-langkah:
☁Penyelesaian :
7 × 6 × 5 × 4 × 3 × 2 =
42 × 5 × 4 × 3 × 2 =
210 × 4 × 3 × 2 =
840 × 3 × 2 =
2.520 × 2 =
5.040
__________________
7! + 3! =
( 7 x 6 x 5 x 4 x 3 x 2 x 1 ) + ( 3 x 2 x 1 ) =
5.040 + 6 =
5.046
__________________
[tex] \tt \frac{1}{2} + \frac{1}{4} = \\ [/tex]
[tex] \tt \frac{2}{4} + \frac{1}{4} = \purple{ \boxed{ \tt \frac{3}{4} }} \\ [/tex]
_______________________________
☁Pelajari lebih lanjut :
________________________________
☁Detail :
Mapel : matematika
Kelas : 12
Bab : Bab 7 - kaidah pepecahan
Kode soal : 2
Kode Kategorisasi : 12.2.7
Kata Kunci : permutasi, kombinasi, faktorial
_____________________
@rasyidafd.ca
#TingkatkanPrestasimu
1. 7 × 6 × 5 × 4 × 3 × 2
= 42 × 5 × 4 × 3 × 2
= 210 × 4 × 3 × 2
= 840 × 3 × 2
= 2.520 × 2
= 5.040
2. 7! + 3!
= ( 7 × 6 × 5 × 4 × 3 × 2 ) + ( 3 × 2 × 1 )
= ( 42 × 5 × 4 × 3 × 2 ) + ( 6 × 1 )
= ( 210 × 4 × 3 × 2) + 6
= ( 840 × 3 × 2 ) + 6
= ( 2.520 × 2 ) + 6
= 5.040 + 6
= 5.046
3. ½ + ¼ =
../4 + ¼
= (4 ÷ 2 × 1)/4 + ¼
= 2/4 + ¼
= ¾