Odpowiedź:
[tex]\displaystyle P(B')=1-P(B)\\ P(B')=1-\frac{13}{30} =\frac{17}{30} \\(A\cup B)'=A'\cap B'\quad \Rightarrow\quad P(A'\cap B')=1-P(A\cup B) \quad \Rightarrow\quad\\P(A'\cap B')=1-\frac{2}{3} =\frac{1}{3} \\P(A'/B')=\frac{P(A' \cap B')}{P(B')} =\frac{\frac{1}{3} }{\frac{17}{30} } =\frac{1}{3} \cdot \frac{30}{17} =\underline{\frac{10}{17} }[/tex]
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Odpowiedź:
[tex]\displaystyle P(B')=1-P(B)\\ P(B')=1-\frac{13}{30} =\frac{17}{30} \\(A\cup B)'=A'\cap B'\quad \Rightarrow\quad P(A'\cap B')=1-P(A\cup B) \quad \Rightarrow\quad\\P(A'\cap B')=1-\frac{2}{3} =\frac{1}{3} \\P(A'/B')=\frac{P(A' \cap B')}{P(B')} =\frac{\frac{1}{3} }{\frac{17}{30} } =\frac{1}{3} \cdot \frac{30}{17} =\underline{\frac{10}{17} }[/tex]