August 2023 0 26 Report
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Tentukan hasil dari penintegralan dibawah ini
[tex]\displaystyle\sf\int\limits_0^{\frac{\pi}{2}} \: \tan^{ -1 } \left(\frac{2a \: { \sin }^{2} x}{1 - {a}^{2} \: { \sin}^{2}x } \right) \: dx[/tex]

[tex]a. \: \pi \: \tan^{ - 1} (a) [/tex]
[tex]b. \: \pi \: { \tan}^{ - 1} \frac{a}{2} [/tex]
[tex]c. \: \tan {}^{2} a[/tex]
[tex]d. \: \pi \: \cot(a) [/tex]

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