Question

Q. Chiiiii rpst`

jIka:
a: 8
b: 25
c: 1/9

[tex]\sf \frac{ {3a}^{ \frac{1}{3} }bc }{ {12a}^{ - 2} {bc}^{ - 3} } = ....[/tex]​

Answer 1

Manipulasi Aljabar

[Bentuk Aljabar, dan Persamaan Eksponen]

..

[tex]\begin{aligned} jika~:~ a &= 8 \\ b &= 25 \\ c &= \frac{1}{9} \end{aligned}[/tex]

[tex] tentukan~: ~ \frac{ {3a}^{ \frac{1}{3} }bc }{ {12a}^{ - 2} {bc}^{ - 3} }[/tex]

Penyelesaian Soal

[tex]\begin{aligned} \frac{ {3a}^{ \frac{1}{3} }bc }{ {12a}^{ - 2} {bc}^{ - 3} } &= \frac{3(8)^{\frac{1}{3}}(25)(\frac{1}{9})}{12(8)^{-2}(25)(\frac{1}{9})^{-3}} \\&= \frac{(2^3)^{\frac{1}{3}} \times \frac{1}{3}}{12(8)^{-2} \times (\frac{1}{9})^{-3}} \\&= \frac{2 \times \frac{1}{3}}{12(8)^{-2} \times (\frac{1}{9})^{-3}} \\&= \frac{\frac{1}{3}}{6(8)^{-2} \times (\frac{1}{9})^{-3}} \\&= \frac{1}{18(8)^{-2} \times (\frac{1}{9})^{-3}} \\&= \frac{8^2}{18 \times 9^3} \\&= \frac{64}{18 \times 9^3} \\&= \frac{32}{9 \times 9^3} \\&= \frac{32}{9^4} \\&= \boxed{\bold{\underline{}\frac{32}{6561}}} \end{aligned}[/tex]

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 01 - 08 - 2023}}[/tex]

Answer 2

Verified answer

Materi : Bentuk Akar dan Pangkat

[tex][tex]\sf \frac{ {3a}^{ \frac{1}{3} }bc }{ {12a}^{ - 2} {bc}^{ - 3} } = ....[/tex][/tex]

{ a = 8, b = 25, c = ⅑ }

_________________/

3a¹/³bc/12a-²bc-³

= ( 3/12 )( a¹/³+² )( b¹-¹ )( c¹+³ )

= ¼ . a⁷/³ . c⁴

= a⁷/³c⁴/4

= (8)⁷/³(⅑)⁴/4

= 2⁷.3-⁸/2²

= 2⁵/3⁸

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[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]