Materi : Bentuk Akar dan Pangkat
[tex][tex] \sf \frac{ {2x}^{3} {y}^{ - 2} }{ {4x}^{2}y } = ...[/tex][/tex]
( 2x³y-² )/( 4x²y )
= ( 2/4 )( x³/x² )( y-²/y )
= ( ½ )( x³-² )( y-²-¹ )
= ( ½ )( x¹ )( y-³ )
= ½ . x . 1/y³
= x/2y³
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
2x³y^-2/4x²y
=2x³/4x²y×y²
=2x³/4x²y³
=x³/2x²y³
=x/2y³
Semoga bermanfaat
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Materi : Bentuk Akar dan Pangkat
[tex][tex] \sf \frac{ {2x}^{3} {y}^{ - 2} }{ {4x}^{2}y } = ...[/tex][/tex]
( 2x³y-² )/( 4x²y )
= ( 2/4 )( x³/x² )( y-²/y )
= ( ½ )( x³-² )( y-²-¹ )
= ( ½ )( x¹ )( y-³ )
= ½ . x . 1/y³
= x/2y³
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Penyelesaian
2x³y^-2/4x²y
=2x³/4x²y×y²
=2x³/4x²y³
=x³/2x²y³
=x/2y³
Semoga bermanfaat