July 2023 1 8 Report
Wykaż, że równość jest tożsamością trygonometryczną.
a) [tex]64(1-sin^2\alpha)(1-sin^22\alpha)(1-sin^24\alpha)=\frac{1-cos^28\alpha}{1-cos^2\alpha}[/tex]
b) [tex](cos\alpha cos2\alpha+cos4\alpha cos8\alpha)^2-(cos\alpha cos2\alpha-cos4\alpha cos8\alpha)^2=\frac{sin16\alpha}{4sin\alpha}[/tex]

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