tolong jawab soal ada di bawah ini
6.
330°=...π
7.
60°=.....π
8.
[tex]tan( \frac{\pi}{6} ) = [/tex]
9.
[tex]sin( \frac{\pi}{4} ) = [/tex]
10.
[tex] \frac{13}{6} \pi = ....[/tex]
6.
330°=...π
7.
60°=.....π
8.
[tex]tan( \frac{\pi}{6} ) = [/tex]
9.
[tex]sin( \frac{\pi}{4} ) = [/tex]
10.
[tex] \frac{13}{6} \pi = ....[/tex]
Jawaban:
f(x) = 4x² + 3x + 8. Hitunglah nilai a + 2b + 3c!
Jawaban:
Diketahui nilai a = 4, b = 3, c = 8
= a + 2b + 3c
= 4 + 2(3) + 3(8)
= 4 + 6 + 24
= 34
2. f(x) = 3x² - 2x + 5 memiliki bentuk sesuai dengan bentuk f(x) = ax² + bx + c. Hitunglah nilai 2a + 3b + 4c!
Jawaban:
= Diketahui nilai a = 3, b = -2, c = 5
= 2a + 3b + 4c
= 2(3) + 3(-2) + (4 x 5)
= 6 - 6 + 20
= 20
3. Diketahui fungsi f(x) = x² + 4x + 5. Hitunglah untuk nilai x = 3
Jawaban:
= f(x) = x² + 4x + 5
= f(3) = 3² + 4(3) + 5
= f(3) = 9 + 12 + 5
= f(3) = 26
Verified answer
Penjelasan dengan langkah-langkah:
1 π = 180⁰
2 π = 360⁰
[tex]6. \: {330}^{0} = \frac{ {330}^{0} }{ {180}^{0} } \pi= \frac{11}{6} \pi = 1 \frac{5}{6} \pi[/tex]
[tex]7. \: {60}^{0} = \frac{ {60}^{0} }{ {180}^{0} } \pi = \frac{1}{6} \pi[/tex]
[tex]8. \: tan( \frac{\pi}{6} ) = tan( \frac{ {180}^{0} }{6 } ) \\ = tan \: {30}^{0} \\ = \frac{1}{3} \sqrt{3} [/tex]
[tex]9. \: sin \: (\frac{\pi}{4}) = sin \: ( \frac{ {180}^{0} }{4} ) \\ = sin \: {45}^{0} \\ = \frac{1}{2} \sqrt{2} [/tex]
[tex]10. \: (\frac{13}{6} )\pi = \frac{13}{6} \times 180 \\ = 13 \times 30 {}^{0} \\ = 390 {}^{0} [/tex]