Question

rozwiąż ......

[tex] (\sqrt{3} + { \sqrt{2} )}^{2} [/tex]

[tex]( {4a}^{2} - \: {2b})^{2} [/tex]
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Answer 1

Verified answer

Odpowiedź:

rozw w zal

Answer 2

WZORY UŻYTE W TYM ZADANIU:

[tex](a +b)^2 = a^2 +2ab+b^2\\(a-b)^2 = a^2 - 2ab + b^2\\[/tex]

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[tex](\sqrt{3} + \sqrt{2})^2 = (\sqrt{3} )^2 + 2 *\sqrt{3}*\sqrt{2} + (\sqrt{2})^2 = 3 + 2\sqrt{6} + 2 = 5 + 2\sqrt{6}\\ \\ (4a^2 - 2b)^2 = (4a^2)^2 - 2*4a^2 *2b + (2b)^2 = 16a^4 - 16a^2b+4b^2[/tex]

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