Question

Soal!!! 15 point

Tentukan nilai X

[tex] \frac{x + 1}{2x - 3} \geqslant 1[/tex]


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Answer 1

Verified answer

Rasioanal
Linier

nilai x

[tex]\sf \dfrac{x+1}{2x-3}\geq 1[/tex]

[tex]\sf \dfrac{x+1}{2x-3} - 1 \geq 0[/tex]

[tex]\sf \dfrac{x+1 - (2x - 3)}{2x-3} \geq 0[/tex]

[tex]\sf \dfrac{x+1 - 2x + 3}{2x-3} \geq 0[/tex]

[tex]\sf \dfrac{4 - x}{2x-3} \geq 0, domain\ x\neq \frac{3}{2}[/tex]

(4 - x)(2x  - 3) ≥ 0
x = 4   atau x =  3/2

- -   (3/2)  + +  [ 4]  - -
hP x  pada  daerah  positif
[tex]\sf HP \ x = \{ x | \ \frac{3}{2} < x \leq 4 \}[/tex]