Question

[tex]a=\sqrt{8}*\sqrt[5]{-32}*4^{-2}[/tex]

Answer 1

[tex]a=\sqrt{8}\cdot\sqrt[5]{-32}\cdot4^{-2}[/tex]

[tex]a=\sqrt{4\cdot2}\cdot(-2)\cdot\dfrac{1}{4^2}[/tex]

[tex]a=2\sqrt{2}\cdot(-2)\cdot\dfrac{1}{16}[/tex]

[tex]a=-4\sqrt{2}\cdot\dfrac{1}{16}[/tex]

[tex]a=-\dfrac{\sqrt{2}}{4}[/tex]