Question

Tentukan terunan dari fungsi brkt:
f(x) = +
f ' (8) = ...

Answer 1

F (x) = ∛x + 1/∛x
f (x) = x¹/³ + 1 / (x¹/³)
f (x) = x¹/³ + x⁻¹/³
f ' (x) = (1/3)x⁻²/³ + (-1/3x⁻⁴/³)
f ' (x) = (1/3) / (x²/³) - (1/3) / (x⁴/³)
f ' (x) = 1 / (3x²/³) - 1 / (3x⁴/³)
f ' (x) = (1 / 3∛x²) - (1 / 3∛x⁴)
f ' (8) = (1 / 3∛(8)²) - (1 / 3∛(8)⁴)
(=) (1 / 3.4) - (1 / 3.16)
(=) 1/12 - 1/48
(=) 4/48 - 1/48
(=) 3/48
(=) 1/16