Question

Tentukan pH larutan:
0,01 mol CH₃COOH dalam 100 ml ( Ka = 1 x 10^₋5)

#MOHON DI BANTU KAK~~

Answer 1

CH3COOH (Ka = 1 × 10^-5)
n = 0,01 mol
V = 100 mL = 100/1000 = 0,1 L

cari Molaritas CH3COOH
M = n/V
M = 0,01/0,1
M = 0,1

cari konsentrasi ion hidrogen
[H^+] = √Ka × Ma
[H^+] = √1 × 10^-5 × 0,1
[H^+] = √10^-6
[H^+] = 10^-3

pH = - log [H^+]
pH = - log 10^-3
pH = 3