Question

Tentukan persamaan garis singgung kurva y= di titik (1,3)

Answer 1

Y = x^1/2 + x^-1/2 + x^-3/2
m= y' = 1/(2√x) - 1/(2x√x) - 3/(2x²√x)
untuk x = 1 ---> m = 1/2 -1/2 - 3/2 = - 3/2
gasing (1,3), m = -3/2
y = -3/2 (x-1) + 3
2y = -3(x-1) + 6
2y= -3x +9
3x +2y - 9 = 0