Question

Tentukan persamaan garis lurus yang melalui titik (3,-6) dan (-1,2)

Answer 1

M = 2+6 / -1-3 = 8/-4 = -2

(3,-6) --> y = mx + c --> -6 = -2 x 3 + c --> -6 = -6 + c --> c = 0

jadi persamaan garisnya :

y = -2x

Answer 2

(3,-6) ---> x₁ = 3 , y₁ = -6
(-1,2) ---> x₂ = -1 , y₂ = 2
Persamaan Garis:
y - y₁  =x - x₁
y₂ - y₁   x₂ - x₁
y - (-6) = x - 3
2 - (-6)    -1 - 3
y + 6 = x - 3
  8          -4
-4(y + 6) = 8( x - 3)
-4y - 24 = 8x - 24
-4y - 24 - 8x + 24 = 0
-8x - 4y = 0