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5x
_________
3 - √(9 + x)
Pakai teorema L'Hospital (Turunan)
5x
= ___________
3 - (9 + x)^½
5
= _______________
0 - ½•1 (9 + x)^-½
5 • (9 + x)^½
= ___________
- ½
5 √(9 + x)
= ___________
-½
5 √(9 + 0)
= ___________
-½
5 √9
= ______
-½
= (5 x 3)/-½
= 15/-½
= -30
Jadi, nilai limitnya adalah -30