Question

Tentukan penyelesaian dari sistem persamaan 2p+3q=12 dan 4p-7q=-2

Answer 1

2p + 3q = 12 (x2)
4p - 7q = -2 (x1)
sehingga
4p + 6q = 24
4p +-7q = -2  -
      13q = 26
         q = 26/13 = 2

cari p, maka subtitusikan q
2p + 3q = 12
2p + (3 x 2) = 12
2p + 6 = 12
2p = 12-6
2p = 6
p = 6/2 = 3

HP = {p,q} = {3,2}

Answer 2

2p + 3q = 12 (x2)
4p - 7q = -2 (x1)

4p + 6q = 24

4 pq -  7q  = - 2  -
         q = 26/13 = 2


2p + 3q = 12
2p + (3 x 2) = 12
2p + 6 = 12
2p = 12-6
2p = 6
p = 6 / 2 = 3


HP = {p,q} = {3,2}