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1. 5p^2 - 3q^2=-3
2p^2 + q^2=34 (×3)
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5p^2 - 3q^2 =-3
6p^2 + 3q^2 =102
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11p^2 =99
p^2 =99/11
p =akar9 =3
p=3
substitusi ke persamaan 2
2(3)^2 + q^2 =34
18 + q^2 =34
q^2 =34-18=16
q= akar16 =4
♧p=3; q=4
nomor 2,3,4 diselesaikan dgn cara yg sama