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x² + (x + c)² = 25
x² + x² + 2cx + c² - 25 = 0
2x² + 2cx + c² - 25 = 0
syarat menyinggung --> D = 0
b² - 4ac = 0
(2c)² - 4.2.(c² - 25) = 0
4c² - 8c² + 200 = 0 --> kedua ruas dibagi 4
c² - 2c + 50 = 0
persamaan tsb jika diakar dgn rumus abc menghasilkan akar yg imajiner.
coba cek soalnya ya.. :)
semoga sedikit membantu :)