Question

Tentukan nilai a agar bentuk x^4-2x^3-(a+1)x^2+(2a+1)x-6 habis dibagi oleh (x+2)

Answer 1

Fungsi

f(x) = x^4 - 2x^3 - (a + 1)x^2 + (2a + 1)x - 6

x + 2 = 0 → x = -2

f(-2) = 0

(-2)^4 - 2.(-2)^3 - (a + 1)(-2)^2 + (2a + 1)(-2) - 6 = 0

16 + 16 - 4a - 4 - 4a - 2 - 6 = 0

-8a + 20 = 0

-8a = -20

a = 20/8

a = 5/2 ✔