Jawab:
A. 4√6 cm².
B. 1.540 cm².
C. 960 cm².
D. 4.106,66 cm³.
E. 616 cm².
Penjelasan dengan langkah-langkah:
A. s = ½ × Keliling Δ
s = ½ × ( 7 + 5 + 4 )
s = ½ × 16
s = 8
L = √ s. (s-a) (s-b) (s-c)
L = √ 8. (8-7)(8-5)(8-4)
L = √ 8.1.3.4
L = √ 96
L = 4√6 cm².
B. L = 2 x phi x r ( r + t )
L = 2 x 22/7 x 7 ( 7 + 28 )
L = 44 x 35
L = 1.540 cm².
C. segitiga 1 (alas = 16 cm)
t1² = sisi miring² - (1/2 x alas)²
t1² = (17 cm)² - (1/2 x 16 cm)²
t1² = 289 cm² - 64 cm² = 225 cm²
t1 = = 15 cm
segitiga 2 (alas = 30 cm)
t2² = sisi miring² - (1/2 x alas)²
t2² = (17 cm)² - (1/2 x 30 cm)²
t2² = 289 cm² - 225 cm² = 64 cm²
t2 = = 8 cm
LP = Luas alas + (2 x luas sisi tegak 1) + (2 x luas sisi tegak 2)
LP = (p x l) + (2 x 1/2 x lebar x t1) + (2 x 1/2 x panjang x t2)
LP = (30 cm x 16 cm) + (2 x 1/2 x 16 cm x 15 cm) + (2 x 1/2 x 30 cm x 8 cm)
LP = 480 cm² + 240 cm² + 240 cm²
LP = 960 cm².
D. Volume kerucut
=1/3×π×r×r×t
=1/3×22/7×14×14×20
=1/3×12.320 cm³
= 4.106,66 cm³.
E. L = 4πr²
= 4×22/7×7×7
= 616 cm².
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Jawab:
A. 4√6 cm².
B. 1.540 cm².
C. 960 cm².
D. 4.106,66 cm³.
E. 616 cm².
Penjelasan dengan langkah-langkah:
A. s = ½ × Keliling Δ
s = ½ × ( 7 + 5 + 4 )
s = ½ × 16
s = 8
L = √ s. (s-a) (s-b) (s-c)
L = √ 8. (8-7)(8-5)(8-4)
L = √ 8.1.3.4
L = √ 96
L = 4√6 cm².
B. L = 2 x phi x r ( r + t )
L = 2 x 22/7 x 7 ( 7 + 28 )
L = 44 x 35
L = 1.540 cm².
C. segitiga 1 (alas = 16 cm)
t1² = sisi miring² - (1/2 x alas)²
t1² = (17 cm)² - (1/2 x 16 cm)²
t1² = 289 cm² - 64 cm² = 225 cm²
t1 = = 15 cm
segitiga 2 (alas = 30 cm)
t2² = sisi miring² - (1/2 x alas)²
t2² = (17 cm)² - (1/2 x 30 cm)²
t2² = 289 cm² - 225 cm² = 64 cm²
t2 = = 8 cm
LP = Luas alas + (2 x luas sisi tegak 1) + (2 x luas sisi tegak 2)
LP = (p x l) + (2 x 1/2 x lebar x t1) + (2 x 1/2 x panjang x t2)
LP = (30 cm x 16 cm) + (2 x 1/2 x 16 cm x 15 cm) + (2 x 1/2 x 30 cm x 8 cm)
LP = 480 cm² + 240 cm² + 240 cm²
LP = 960 cm².
D. Volume kerucut
=1/3×π×r×r×t
=1/3×22/7×14×14×20
=1/3×12.320 cm³
= 4.106,66 cm³.
E. L = 4πr²
= 4×22/7×7×7
= 616 cm².
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