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Verified answer
PerSamaAn LingkaranBentuk Umum :
x² + y² + Ax + By + C = 0
Pusat = (-1/2 A , -1/2 B)
r = √((-1/2 A)² + (-1/2 B)² - C)
2x² + 2y² + 8x + 12y - 2 = 0
kedua ruas dibagi 2
x² + y² + 4x + 6y - 1 = 0
A = 4
B = 6
C = -1
r = √((-1/2 . 4)² + (-1/2 . 6)² - (-1))
r = √((-2)² + (-3)² + 1)
r = √(4 + 9 + 1)
r = √14 satuan
Jawabannya:
Persamaan Lingkaran
Bentuk Umum:
x2+y2+Ax+By+C=0
Pusat=(-1/2A 1/2B)
r=Akar[(-1/2 A)2+(-1/2 B)2-C]
2x+2y+8x+12y-2=0
kedua ruasnya kita bagi 2
x2+y2+4+6y+(-1)=0
A=6
B=4
C=-1
r=Akar[(-1/2.4)2+(-1/2.6)2-(-1)]
r=Akar[(-2)2+(-3)2+1
r=Akar(4+9+1)
r=Akar(13+1)
r=Akar(14)
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