Penjelasan dengan langkah-langkah:
a. f(x) = √(3x-1) × 2
y = √(3x-1) × 2
y² = [√(3x-1) × 2]²
y² = (3x-1) × 4
y² = 12x-4
12x = y²+4
x = y²+4/12
f^-1(x) = (x²+4)/12
[tex]\bold {f}^{ - 1} (x) = \frac{{x}^{2} + 4 }{12}
\\ [/tex]
b. f(x) = 2x-4
y = 2x-4
y+4=2x
2x=y+4
x=y+4/2
f^-1(x) = (x+4)/2
[tex]\bold f^{-1}(x)=\frac{x+4}{2}[/tex]
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Verified answer
Penjelasan dengan langkah-langkah:
a. f(x) = √(3x-1) × 2
y = √(3x-1) × 2
y² = [√(3x-1) × 2]²
y² = (3x-1) × 4
y² = 12x-4
12x = y²+4
x = y²+4/12
f^-1(x) = (x²+4)/12
[tex]\bold {f}^{ - 1} (x) = \frac{{x}^{2} + 4 }{12}
\\ [/tex]
b. f(x) = 2x-4
y = 2x-4
y+4=2x
2x=y+4
x=y+4/2
f^-1(x) = (x+4)/2
[tex]\bold f^{-1}(x)=\frac{x+4}{2}[/tex]