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∫ (6x²- 2/x²) dx
1
4
= ∫ (6x² - 2x⁻²) dx
1
4
= 2x³ + 2x⁻¹ I
1
4
= 2x³ + 2/x I
1
= [ 2(4)³) + 2/4 ] - [2(1)³ + 2/1 ]
= 128,5 - 4
= 124,5
Jadi, hasil pengintegralannya adalah 124,5