Question

Tentukan hasil pengkuadratan berikut.
a. (3+√8)²
b. (7-√6)²
c. (√5+√8)²
d. (3√2-2√5)²

Answer 1

A. (3+√8)² = (3)² +(√8)² = 9+8 = 17
b.(7)²-(√6)²=49-6=43
c.(√5)²+(√8)²=5+8=13
d.(3√2)²-(2√5)²={(3)².(√2)²}-{(2)².(√5)²}
={(9.2)-(4.5)}=18-20=-2

Answer 2

A. (3 + √8)^2
= 3^2 + 2(3)(√8) + (√8)^2
= 9 + 6 √8 + 8
= 17 + 6 √(4 × 2)
= 17 + 6 √(2^2 × 2)
= 17 + (6 × 2) √2
= 17 + 12 √2

b. (7 - √6)^2
= 7^2 + 2(7)(- √6) + (- √6)^2
= 49 - 14 √6 + 6
= 55 - 14 √6

c. (√5 + √8)^2
= (√5)^2 + 2(√5)(√8) + (√8)^2
= 5 + 2 √40 + 8
= 13 + 2 √(4 × 10)
= 13 + 2 √(2^2 × 10)
= 13 + (2 × 2) √10
= 13 + 4 √10

d. (3 √2 - 2 √5)^2
= (3 √2)^2 + 2(3 √2)(-2 √5) + (-2 √5)^2
= 9 × 2 - 12 √10 + 4 × 5
= 18 - 12 √10 + 20
= 38 - 12 √10

^ = pangkat

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