Question

Tentukan hasil dari operasi aljabar berikut!
1. (2x+7)(3x+5
2. (5x-1)(x+8)
3. 24x^5y^3 : 14xy
4. (3x+5)^3

Yang jago mtk mohon dibantu secepatnya. Saya akan beri 25 poin. Mksih.

Answer 1

1. (2x+7)(3x+5)
= 2x.3x+7.3x+2x.5+7.5 = 6x²+21x+10x+35 =6x²+31x+35
2. (5x-1)(x+8)
= 5x.x-1.x+5x.8-1.8 = 5x²-x+40x-8 = 5x²+39x-8
3. 24x⁵y³ / 14xy
= 24/14 x⁵⁻¹y³⁻¹ = 12/7 x⁴y²
4. (3x+5)³
= (3x+5)(3x+5)(3x+5) = (3x.3x+5.3x+3x.5+5.5)(3x+5)
= (9x²+30x+25)(3x+5) = (9x².3x+9x².5+30x.3x+30x.5+25.3x+25.5)
= 27x³+45x²+90x²+150x+75x+125 = 27x³+135x²+225x+125 

Answer 2

1. (2x+7)(3x+5)= 6x^2+10x+21x+35=6x^2+31x+35
2. (5x-1)(x+8) = 5x^2+40x-x-8= 5x^2+39x-8
3. 24x^5y^3:14xy =7/12x^4y^2, itu yg 7/12 per ya maksudnya

4.(3x+5)^3= a^3+3a^2b+3ab^2+b^3
= (3x)^3 + 3(3×)^2.5+ 3(3x)(5)^2+(5)^3
= 27x^3+ 135x^2+225x+125