Question

Tentukan hasil dari :
b. (4x + 3y)(16x^2 - 12xy + 9y)^2
d. (4x - 3y)^2 - (3x - 4y)^2

#TentangAljabar

Answer 1

b. (4x + 3y)(16x^2 - 12xy + 9y)^2
=(4x + 3y)[16x^2 - (12xy - 9y)]^2
=(4x+3y)[256x^4 - 2(16x^2)(12xy-9y) +81y^2]
=(4x+3y)(256x^4 - 384x^3y-288x^2y +81y^2)
=4x(256x^4 - 384x^3y-288x^2y +81y^2)
+3y(256x^4 - 384x^3y-288x^2y +81y^2)
=1024x^5 -1536x^4y -1152x^3y +324xy^2
+768x^4y -1152x^3y^2 -864x^2y^2 +243y^3
=024x^5 -768x^4y -1152x^3y +324xy^2
-1152x^3y^2 -864x^2y^2 +243y^3

d. (4x - 3y)^2 - (3x - 4y)^2
= [(4x - 3y) - (3x - 4y)] [(4x - 3y) + (3x - 4y)]
= (x+y)(7x -7y)
= x(7x -7y) +y(7x -7y)
= 7x² - 7xy + 7xy - 7y²
= 7x² - 7y²


Catatan

(4x-3y)²- (3x-4y)² =7x² - 7y² =7(x² - y²)
=7(x+y)(x-y) ....(bila ingin hasilnya dalam perkalian faktor)

(4x-3y)²- (3x-4y)² =7x² - 7y²
....(bila ingin hasilnya dalam penjumlahan suku-suku)



Selamat belajar !
@Wello1☺