Tentukan harga pH dan pOH .
jika 17,1 gr Ba(OH)2. dilarutkan dalam air sehingga volume larutan menjadi 500 ml.
bantu ya
jika 17,1 gr Ba(OH)2. dilarutkan dalam air sehingga volume larutan menjadi 500 ml.
bantu ya
Risep
Mr Ba(OH)₂ = 171
![M= \frac{gr/Mr}{V} \\ \\ = \frac{17,1/171}{0,5}=0,2~M \\ \\ ~[OH^-]=b.M \\ \\ =2.2.10^{-1}=4.10^{-1}~M \\ \\ \\ pOH=-log 4.10^{-1}=1-log4 \\ \\ pH=14-pOH=14- (1-log4)=13+log4](https://tex.z-dn.net/?f=M%3D+%5Cfrac%7Bgr%2FMr%7D%7BV%7D+%5C%5C++%5C%5C+%3D+%5Cfrac%7B17%2C1%2F171%7D%7B0%2C5%7D%3D0%2C2%7EM+%5C%5C++%5C%5C+%7E%5BOH%5E-%5D%3Db.M+%5C%5C++%5C%5C+%3D2.2.10%5E%7B-1%7D%3D4.10%5E%7B-1%7D%7EM+%5C%5C++%5C%5C++%5C%5C+pOH%3D-log+4.10%5E%7B-1%7D%3D1-log4+%5C%5C++%5C%5C+pH%3D14-pOH%3D14-+%281-log4%29%3D13%2Blog4 "M= \frac{gr/Mr}{V} \\ \\ = \frac{17,1/171}{0,5}=0,2~M \\ \\ ~[OH^-]=b.M \\ \\ =2.2.10^{-1}=4.10^{-1}~M \\ \\ \\ pOH=-log 4.10^{-1}=1-log4 \\ \\ pH=14-pOH=14- (1-log4)=13+log4")
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