Question

Tentukan hambatan kawat almunium(hambatan jenis 0,03)jika panjang kawat 2mm dan diameter kawat 42mm
pliss bantuin dongk
yg bantuin jajakumullah

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Answer 1

R= ρ l / A
ρ  = 0,03 ohm .m
l = 2mm = 2 x 10^-3 m
d= 42 mm --> r = 21 mm = 21x10^-3
A = 22/7 (21 x10^-3)^2
A = 22/7 (441 x 10^-6)
A= 1.386 x 10-6= 1,386 x 10^-9
R = (0,03)(2x10^-3) / ( 1,386 x 10^-9)
R = 0,043 x 10^-3 x 10^9
R = 0,043 x 10^6