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Pembahasan
A(-3,0) , B(-1,1).
(x1,y1) (a,b)
Langkah pertama kita harus mencari nilai r
r =
r = √5
rumus
(x - a)(x1 - a) + (y - b)(y1 - b) = r^2
masukan angka angka yang diketahui ke dalam rumus
(x - (-1))((-3)- (-1)) + (y - 1)(0 - 1) = 5
(x +1)(-2) + (y-1)(-1) = 5
(-2x - 2) + (-y + 1) = 5
-2x - y -2+1 - 5 = 0
-2x - y - 6 = 0
Semoga membantu :) R