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Yang boleh dioperasikan hanya yang sama angka pertamanyaa. (f+g)(x) = {(1, 3+1),(2,2+3), (3,1+5)} = {(1,4),(2,5),(3,6)}
b. (f.g)(x) = {(1, 3.1),(2,2.3), (3,1.5)} ={(1,3),(2,6),(3,5)}
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Hasil operasi fungsi merupakan hasil operasi nilai fungsi pada titik tertentu.(f + g)(x) = f(x) + g(x)
a)
(f + g)(1) = f(1) + g(1) = 3 + 1 = 4
(f + g)(2) = f(2) + g(2) = 2 + 3 = 5
(f + g)(3) = f(3) + g(3) = 1 + 5 = 6
(f + g)(4) = f(4) + g(4) tidak bisa dioperasikan, karena nilai g(4) tidak terdefinisi
Jadi (f + g)(x) = { (1,4) , (2,5) , (3,6) }
(f . g)(x) = f(x) . g(x)
b)
(f . g)(1) = f(1) . g(1) = 3 . 1 = 3
(f . g)(2) = f(2) . g(2) = 2 . 3 = 6
(f . g)(3) = f(3) . g(3) = 1 . 5 = 5
(f . g)(4) = f(4) . g(4) tidak bisa dioperasikan, karena nilai g(4) tidak terdefinisi
Jadi (f . g)(x) = { (1,3) , (2,6) , (3,5) }
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