Question

tentukan daerah yang di arsir ,jika rumus luas lingkaran πr²(π=3,14)​

Answer 1

Jawaban:

132,665 cm²

Penjelasan dengan langkah-langkah:

D1 = 5 cm

D2 = 12 cm

D3 = 13 cm

..

D3² = D1² + D2²

D3² = 5² + 12²

D3² = 25 + 144

D3² = 169

D3 = √169

D3 = 13 cm

..

masing2 sisi segitiga adalah diameter setengah lingkaran

maka:

L = 1/2 × π × r²

..

LD1 = 1/2 × 3,14 × 2,5²

LD1 = 9,8125 cm²

..

LD2 = 1/2 × 3,14 × 6²

LD2 = 56,52 cm²

..

LD3 = 1/2 × 3,14 × 6,5²

LD3 = 66,3325 cm²

..

Luas yang diarsir

= LD1 + LD2 + LD3

= 9,8125 + 56,52 + 66,3325

= 132,665 cm²

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at}}[/tex]

Answer 2

D = √5² + 12²

= √(5(5) + (12(12)

= √25 + 144

= √169

= √13²

= 13 CM

MAKA :

R1 = 5/2 = 2,5 CM

L = (1/2(3,14(2,5(2,5)

= (1/2(3,14(6,25)

= (1/2(19,625)

= 19,625/2

= 9,8125 CM²

R2 = 12/2 = 6 CM

L = (1/2(3,14(6(6)

= (1/2(3,14(36)

= (1/2(113,04)

= 113,04/2

= 56,52 CM²

R3 = 13/2 = 6,5 CM

L = (1/2(3,14(6,5(6,5)

= (1/2(3,14(42,25)

= (1/2(132,665)

= 132,665/2

= 66,3325 CM²

LA :

= (9,8125 + 56,52 + 66,3325)CM²

= (9,8125 + 122,8525)CM²

= 132,665 CM²

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