Tentang notasi sigma.. mohon bantuanya kakak :D + caranya :v.... Question from @Wahyupurnamaa

DB45 A). 3,5,7,...,51
a= 3, b = 2
Un = a +(n-1)b --> Un = 2n + 1
Un = 51 --> 2n -1= 51 --> n =25
.
25
∑ 2n+1
n = 1
.

b) 1/2, 1/4, 1/8, 1/16, 1/32
n= 1 --> 1/2 = 1/2
n = 2 --> 1/4 = (1/2)²
n = 3 --> 1/8 = (1/2)³
..
n= 5 --> 1/32 =(1/2)⁵
..
5
∑ (1/2)ⁿ
n = 1
.

c) 2,4,8,16,32,64
n =1 --> 2 = 2¹
n = 2 -->4 = 2²
n= 3 --> 8 = 2³
..
n = 6 --> 64 = 2⁶
.
6
∑ (2)ⁿ
n=1
.
d. 2, -4, 8 , - 16, 32, - 64
n = 1 --> 2 = -(-2)¹
n = 2 --> -4= -(-2)²
..
n = 6 --> -64 = -(-2)⁶
.
6
∑ -(-2)ⁿ
n =1

2 votes Thanks 2

whongaliem a) 3 + 5 + 7 ....+ 51   ⇒ a = 3 ; b = 2 ; Un = 51
Un = a + (n - 1).b
51 = 3 + (n - 1).2
51 = 3 + 2n - 2
51 = 1 + 2n
2n = 51 - 1
2n = 50
n = 50/2
n = 25

25
∑ 2n + 1
i=1

b) 1/2 + 1/4 + 1/8 + 1/16 + 1/32 ⇒ a = 1/2 . r = 1/2 = 2^-1 ; n = 5

$Un = a. r^{n - 1}$

$Un = 2^{- 1} (2^{- 1} )^{n - 1}$

$Un = 2^{- 1} .2^{- n + 1}$

$Un = 2^{- n}$

5
   ∑ $2^{- 1}$
i = 1

c) 2 + 4 + 8 + 16 + 32 + 64 ⇒ a = 2 ; r = 4/2 = 2 ; n = 6

$Un = a . r^{n - 1}$

$Un = 2 . 2^{n - 1}$

$Un = 2^{n}$

6
  ∑ $2^{n}$
i = 1

d) 2 - 4 + 8 - 16 + 32 - 64 ⇒ a = 4 ; b = - 4 /2 = - 2 ; n = 6

   $Un = a . r^{n - 1}$

   $Un = 2 . (- 2)^{n - 1}$

6
   ∑ $2 . (- 2)^{n - 1}$
i = 1

1 votes Thanks 1

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