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arg z = tan t = (im/real)
tan t = (-√3 / 3)
arc tan (-√3 / 3) = t
t = 150°
r = √(x² + y²)
= √(3² +(-√3)²)
= √(9 + 3)
= √12
= 2√3
koordinat polar = (2√3, 150°)
z = 2√3(cos150° +i.sin150°)
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2√3(cos150° +i.sin150°) = 2√3.cis150°
= 2√3.e^(i.150°)
Jadi, bentuk kutubnya = 2√3(cos150° +i.sin150°)
dan bentuk eksponennya = 2√3.e^(i.150°)
CMIIW