Penjelasan dengan langkah-langkah:
r = 3 m
t = 4 m
s = √(3²+4²)
s = √(9+16)
s = √25
s = 5 m
Luas bahan = Luas permukaan kerucut
= πr(r + s)
= π × 3 × ( 3 + 5)
= 3π × 8
= 24π
= 24 × 3,14
= 62,8 + 12,56
___________________________________________
G Pelukis = √r² + t²
G Pelukis = √3² + 4²
G Pelukis = √9 + 16
G Pelukis = √25
G Pelukis = √5²
G Pelukis = 5 cm
L Terpal = π × r × (r + s)
L Terpal = 22/7 × 3 × (3 + 5)
L Terpal = 22/7 × 3 × 8
L Terpal = 22/7 × 24
L Terpal = 75,42 cm²
Atau
L Terpal = 3,14 × 3 × (3 + 5)
L Terpal = 3,14 × 3 × 8
L Terpal = 3,14 × 24
L Terpal = 75,36 cm²
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Penjelasan dengan langkah-langkah:
r = 3 m
t = 4 m
s = √(3²+4²)
s = √(9+16)
s = √25
s = 5 m
Luas bahan = Luas permukaan kerucut
= πr(r + s)
= π × 3 × ( 3 + 5)
= 3π × 8
= 24π
= 24 × 3,14
= 62,8 + 12,56
= 75,36 m²
SOAL 1
___________________________________________
G Pelukis = √r² + t²
G Pelukis = √3² + 4²
G Pelukis = √9 + 16
G Pelukis = √25
G Pelukis = √5²
G Pelukis = 5 cm
___________________________________________
L Terpal = π × r × (r + s)
L Terpal = 22/7 × 3 × (3 + 5)
L Terpal = 22/7 × 3 × 8
L Terpal = 22/7 × 24
L Terpal = 75,42 cm²
Atau
L Terpal = π × r × (r + s)
L Terpal = 3,14 × 3 × (3 + 5)
L Terpal = 3,14 × 3 × 8
L Terpal = 3,14 × 24
L Terpal = 75,36 cm²
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