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4=12*R2/(12+R2)
48+4R2=12R2
-8R2=-48
R2=6Ω
Rz=R1+R2=12+6=18
1/4 = 1/12 + 1/R
czyli R = 6Ω
połączenie szeregowe:
Rz = 12 + 6 = 18Ω